0=u^2+32u-60

Solution for 0=u^2+32u-60 equation:

0=u^2+32u-60

We move all terms to the left:

0-(u^2+32u-60)=0

We add all the numbers together, and all the variables

-(u^2+32u-60)=0

We get rid of parentheses

-u^2-32u+60=0

We add all the numbers together, and all the variables

-1u^2-32u+60=0

a = -1; b = -32; c = +60;
Δ = b2-4ac
Δ = -322-4·(-1)·60
Δ = 1264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1264}=\sqrt{16*79}=\sqrt{16}*\sqrt{79}=4\sqrt{79}$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-4\sqrt{79}}{2*-1}=\frac{32-4\sqrt{79}}{-2}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+4\sqrt{79}}{2*-1}=\frac{32+4\sqrt{79}}{-2}
$